if i stick with the 9 GPM which produces 2150 PSI. do you have any suggestions on which motor to put on a 4 " pto driven bush hog. I was going with a 5 ft untill i found out it was a 9 instead of 14.5 GPM Not sure if the size bushhog makes a difference on what i can do. I just purchased some land with 5 yr old planted pines and the underbrush has never been cut. im hoping that i can clear this with this skid steer.
There are a lot of variables to consider here.. Like if there is a gear box on the mower and all the points Ken made above. Generally speaking, mowing any kind of heavy brush or grass sucks a lot of horsepower. Theoretically you could cut it with about any combination imaginable if you went slow enough, but there are limits to all of our patience.
Some food for thought...
- Take a look at some commercially available mowers for SSL's (just on websites or the such). Find one that is reasonably sized for your machine flow and pressure. Note the pressure and flow ratings of this mower. If you don't find one, that is telling you something....
- Multiply the pressure (in PSI) times the flow (in GPM) and divide by 1714. This should be the HP demanded by the mower. I would then divide this by 0.8 or even 0.7 to account for the losses of the hydraulic system. The resulting number is essentially the HP needed to run the similar mower at max performance.
- Keep in mind you need some HP left over to drive the machine and you don't want to be running your machine at full HP demand for a long period of time. If you operate on hills this demand will be higher. If you operate very slowly on flat ground it will be lower. I would plan on NO MORE than 60% of the max HP of the engine going to the mower.
- Based on the above, does your machine have enough HP? If yes, continue. If no, or if you are very close, you are better off finding another solution. Otherwise you will either be frustrated by how slow you have to go or be killing your machine. In the second case, I would probably look for a small farm tractor to do the job. My gut tells me you are going to be in the second situation. Note that even if you have enough engine HP, you may not have enough hydraulic or engine cooling capacity. If this is the case it will mean that you will only be able to mow in short bursts with stops (engine still running) to let the machine cool itself down. The small Skattraks I have worked with have not proven to be the best cooling machines. Of course the weather makes some difference here, but not as much as you might think unless you plan to mow in the dead of winter.
- If you think you will have enough engine HP, then you can back calculate to find what flow should run your mower at a reasonable speed given your pressure. This is assuming the reference mower from above is very similar in width and general design and does not have a gearbox on it. Since you want the HP demand of the mower to equal the HP above that you calculated, you can use the same equation and just solve for flow instead of HP. i.e. HP needed = Machine pressure * Needed motor flow/1714. Solve for needed motor flow... or... Needed Flow = HP needed*1714/Machine Pressure.
- Then figure what speed you want your mower to spin at... If it was a pto mower with no gearbox, then this is either 540 or 1170. Take the flow from above and divide by the rpm desired. This will give you gallons/rev for the pump. Convert gallons to cubic inch or cubic centimeters or whatever your pump stats are in, and you have the displacement of the motor you need.
If your mower or the reference mower has a gearbox there is another level of calcuation that I won't bore you with (probably already did that well enough).
I hope I wrote this all out correctly... I was doing this in my head while suffering from a bit of insomnia. If I did it wrong you should end up with some really crazy numbers that don't make sense. A good guy at your local hydraulics shop should be able to help you out if needed....
Sorry for the long explanation.... Hopefully it helps me sleep...