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hydraulic force
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<blockquote data-quote="craigb93" data-source="post: 46767" data-attributes="member: 4541"><p>Force= Line pressure times Cylinder Bore Area. I should think the *42 series Bobcats have a relief valve pressure of 2300 psi. Cylinder Area= Pi/4 x Dia x Dia. Pi/4= 0.7854 Your 2.5" cyl would deliver 2300*0.7854*2.5*2.5=11,300 lb A 4" cyl would deliver 28,900 lbf. A single cyl splitter would be superior to two cyls in parallel as the blade would cock and bind on the slide with any un-even cyl leakage that makes the force unbalanced. Craigb</p></blockquote><p></p>
[QUOTE="craigb93, post: 46767, member: 4541"] Force= Line pressure times Cylinder Bore Area. I should think the *42 series Bobcats have a relief valve pressure of 2300 psi. Cylinder Area= Pi/4 x Dia x Dia. Pi/4= 0.7854 Your 2.5" cyl would deliver 2300*0.7854*2.5*2.5=11,300 lb A 4" cyl would deliver 28,900 lbf. A single cyl splitter would be superior to two cyls in parallel as the blade would cock and bind on the slide with any un-even cyl leakage that makes the force unbalanced. Craigb [/QUOTE]
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